3.9.26 \(\int \frac {(c x^2)^{3/2}}{x^7 (a+b x)} \, dx\)

Optimal. Leaf size=112 \[ -\frac {b^3 c \sqrt {c x^2} \log (x)}{a^4 x}+\frac {b^3 c \sqrt {c x^2} \log (a+b x)}{a^4 x}-\frac {b^2 c \sqrt {c x^2}}{a^3 x^2}+\frac {b c \sqrt {c x^2}}{2 a^2 x^3}-\frac {c \sqrt {c x^2}}{3 a x^4} \]

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Rubi [A]  time = 0.03, antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {15, 44} \begin {gather*} -\frac {b^2 c \sqrt {c x^2}}{a^3 x^2}-\frac {b^3 c \sqrt {c x^2} \log (x)}{a^4 x}+\frac {b^3 c \sqrt {c x^2} \log (a+b x)}{a^4 x}+\frac {b c \sqrt {c x^2}}{2 a^2 x^3}-\frac {c \sqrt {c x^2}}{3 a x^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(c*x^2)^(3/2)/(x^7*(a + b*x)),x]

[Out]

-(c*Sqrt[c*x^2])/(3*a*x^4) + (b*c*Sqrt[c*x^2])/(2*a^2*x^3) - (b^2*c*Sqrt[c*x^2])/(a^3*x^2) - (b^3*c*Sqrt[c*x^2
]*Log[x])/(a^4*x) + (b^3*c*Sqrt[c*x^2]*Log[a + b*x])/(a^4*x)

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[(a^IntPart[m]*(a*x^n)^FracPart[m])/x^(n*FracPart[m]), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {\left (c x^2\right )^{3/2}}{x^7 (a+b x)} \, dx &=\frac {\left (c \sqrt {c x^2}\right ) \int \frac {1}{x^4 (a+b x)} \, dx}{x}\\ &=\frac {\left (c \sqrt {c x^2}\right ) \int \left (\frac {1}{a x^4}-\frac {b}{a^2 x^3}+\frac {b^2}{a^3 x^2}-\frac {b^3}{a^4 x}+\frac {b^4}{a^4 (a+b x)}\right ) \, dx}{x}\\ &=-\frac {c \sqrt {c x^2}}{3 a x^4}+\frac {b c \sqrt {c x^2}}{2 a^2 x^3}-\frac {b^2 c \sqrt {c x^2}}{a^3 x^2}-\frac {b^3 c \sqrt {c x^2} \log (x)}{a^4 x}+\frac {b^3 c \sqrt {c x^2} \log (a+b x)}{a^4 x}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 65, normalized size = 0.58 \begin {gather*} -\frac {\left (c x^2\right )^{3/2} \left (a \left (2 a^2-3 a b x+6 b^2 x^2\right )-6 b^3 x^3 \log (a+b x)+6 b^3 x^3 \log (x)\right )}{6 a^4 x^6} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(c*x^2)^(3/2)/(x^7*(a + b*x)),x]

[Out]

-1/6*((c*x^2)^(3/2)*(a*(2*a^2 - 3*a*b*x + 6*b^2*x^2) + 6*b^3*x^3*Log[x] - 6*b^3*x^3*Log[a + b*x]))/(a^4*x^6)

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IntegrateAlgebraic [A]  time = 0.07, size = 69, normalized size = 0.62 \begin {gather*} \left (c x^2\right )^{3/2} \left (-\frac {b^3 \log (x)}{a^4 x^3}+\frac {b^3 \log (a+b x)}{a^4 x^3}+\frac {-2 a^2+3 a b x-6 b^2 x^2}{6 a^3 x^6}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(c*x^2)^(3/2)/(x^7*(a + b*x)),x]

[Out]

(c*x^2)^(3/2)*((-2*a^2 + 3*a*b*x - 6*b^2*x^2)/(6*a^3*x^6) - (b^3*Log[x])/(a^4*x^3) + (b^3*Log[a + b*x])/(a^4*x
^3))

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fricas [A]  time = 1.01, size = 59, normalized size = 0.53 \begin {gather*} \frac {{\left (6 \, b^{3} c x^{3} \log \left (\frac {b x + a}{x}\right ) - 6 \, a b^{2} c x^{2} + 3 \, a^{2} b c x - 2 \, a^{3} c\right )} \sqrt {c x^{2}}}{6 \, a^{4} x^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2)^(3/2)/x^7/(b*x+a),x, algorithm="fricas")

[Out]

1/6*(6*b^3*c*x^3*log((b*x + a)/x) - 6*a*b^2*c*x^2 + 3*a^2*b*c*x - 2*a^3*c)*sqrt(c*x^2)/(a^4*x^4)

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2)^(3/2)/x^7/(b*x+a),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,x):;OUTPUT:Warn
ing, integration of abs or sign assumes constant sign by intervals (correct if the argument is real):Check [ab
s(x)]Sign error (%%%{a,0%%%}+%%%{b,1%%%})

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maple [A]  time = 0.01, size = 62, normalized size = 0.55 \begin {gather*} -\frac {\left (c \,x^{2}\right )^{\frac {3}{2}} \left (6 b^{3} x^{3} \ln \relax (x )-6 b^{3} x^{3} \ln \left (b x +a \right )+6 a \,b^{2} x^{2}-3 a^{2} b x +2 a^{3}\right )}{6 a^{4} x^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2)^(3/2)/x^7/(b*x+a),x)

[Out]

-1/6*(c*x^2)^(3/2)*(6*b^3*ln(x)*x^3-6*b^3*ln(b*x+a)*x^3+6*a*b^2*x^2-3*a^2*b*x+2*a^3)/x^6/a^4

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maxima [A]  time = 1.45, size = 66, normalized size = 0.59 \begin {gather*} \frac {b^{3} c^{\frac {3}{2}} \log \left (b x + a\right )}{a^{4}} - \frac {b^{3} c^{\frac {3}{2}} \log \relax (x)}{a^{4}} - \frac {6 \, b^{2} c^{\frac {3}{2}} x^{2} - 3 \, a b c^{\frac {3}{2}} x + 2 \, a^{2} c^{\frac {3}{2}}}{6 \, a^{3} x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2)^(3/2)/x^7/(b*x+a),x, algorithm="maxima")

[Out]

b^3*c^(3/2)*log(b*x + a)/a^4 - b^3*c^(3/2)*log(x)/a^4 - 1/6*(6*b^2*c^(3/2)*x^2 - 3*a*b*c^(3/2)*x + 2*a^2*c^(3/
2))/(a^3*x^3)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (c\,x^2\right )}^{3/2}}{x^7\,\left (a+b\,x\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2)^(3/2)/(x^7*(a + b*x)),x)

[Out]

int((c*x^2)^(3/2)/(x^7*(a + b*x)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (c x^{2}\right )^{\frac {3}{2}}}{x^{7} \left (a + b x\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2)**(3/2)/x**7/(b*x+a),x)

[Out]

Integral((c*x**2)**(3/2)/(x**7*(a + b*x)), x)

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